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Physical Pendulum

A ruler, a disc or a ring swinging on a nail is not a weight on a string: its mass is spread out. Find how long one swing takes, where to put the pivot for a given period, or what g is.

MechanicsOscillationsMoment of inertia
Inputs
Input examples
Choose the shape, then click Solve next to the quantity you want to find. d is the distance from the pivot to the centre of the object. For Any object, enter its radius of gyration k = √(I/m) about its centre. Small swings are assumed; the mass does not matter.

What is a Physical Pendulum?

Any rigid object that swings about a pivot is a physical pendulum. Its period depends on how its mass is spread out, through the moment of inertia I about the pivot. A metre stick swinging from one end beats faster than a 1 m string pendulum, because part of its mass sits close to the pivot.

Moving the pivot towards the centre first makes the swing faster, then — very close to the centre — much slower. The fastest swing comes when the pivot is one radius of gyration k from the centre.

rodk² = L²/12
disck² = R²/2
ringk² = R²
d = kfastest swing

Period and Pivot Position

period
period for each pivot position
your pivot
fastest swing (d = k)
edge of the object
Result
Enter the values above

Swinging from the Edge

Earth, small swings
ObjectPivotSame as a string ofPeriod
Rod, 1 mone end⅔ L = 0.667 m1.64 s
Disc, R = 20 cmthe rim1.5 R = 0.30 m1.10 s
Ring, R = 20 cmthe rim2 R = 0.40 m1.27 s
Simple pendulum, 1 m—1 m2.01 s

Worked Techniques

Parallel-Axis Theorem

The moment of inertia about the pivot is the one about the centre plus m d². Dividing by m gives k² + d², so the mass cancels from the period.

Example: 
Equivalent String Length

A physical pendulum swings like a simple pendulum of length Leq. That point below the pivot is the centre of oscillation.

Example: metre stick from one end: Leq = 0.667 m.
Two Pivots, One Period

For a given period there are usually two pivot positions, one on each side of d = k. Their product is k².

Example: 1 m rod, T = 1.8 s: d = 0.122 m or 0.683 m.

Sources & Verification

References
  1. D. Halliday, R. Resnick & J. Walker, Fundamentals of Physics, 10th ed., Wiley, 2014 — Ch. 10 (Rotation) and Ch. 15 (Oscillations).